python 正则找到规律数据

[fortunezhang]

字符串： <Data>1=1&2=2</Data><Data>abc</Data><Data>nihao</Data>
我想找到得到的是['1=1&2=2','abc','nihao']
请各位帮忙解答一下，本人python菜鸟，勿喷，谢谢。

[c]

re.findall('<Data>([^<]+)</Data>', s)

[Kai]

移动到 /go/python

[ChanneW]

def tsplit(string, delimiters):
"""Behaves str.split but supports multiple delimiters."""

delimiters = tuple(delimiters)
stack = [string,]

for delimiter in delimiters:
for i, substring in enumerate(stack):
substack = substring.split(delimiter)
stack.pop(i)
for j, _substring in enumerate(substack):
stack.insert(i+j, _substring)

return stack

s ="<Data>1=1&2=2</Data><Data>abc</Data><Data>nihao</Data>"
tsplit(s, (',', '<Data>', '</Data>'))

[uJohnny]

如果只是标签里的数据, 用lxml吧.
不想用的话, 就参考下这个: http://bit.ly/1qHjIeV

[fortunezhang]

@Kai 不知道怎么移动了。下次注意。thx

[irosyking]

正则表达式为 (?<=<data>)(.*?)(?=<\/data>)

import re

m=re.findall(r'(?<=<data>)(.*?)(?=<\/data>)','<Data>1=1&2=2</Data><Data>abc</Data><Data>nihao</Data>',re.I|re.M)

print m