晕了，求助一个正则如何写,要把圆括号里面的内容取出来

[RangerWolf]

比如有 aa(bbb)ccc
我只会一个 \(.*\)
但是这样会把圆括号也带上， 即输出: (bbb)
有没有能只取出圆括号里面的内容的正则？ 不带圆括号...

[rming]

http://3v4l.org/EH4Ca

[weyou]

用正则的group啊， \((.*)\)

[weyou]

>>> import re
>>> a = "this is a (test), isn't it"
>>> re.search(r'\((.*)\)', a).group(1)
'test'

[RangerWolf]

@weyou 感谢~ 如果是仅 .group() 不是 group(1)的话 还是会带圆括号

[zhyu]

@RangerWolf
re.MatchObject.group([group1, ...])

Returns one or more subgroups of the match. If there is a single argument, the result is a single string; if there are multiple arguments, the result is a tuple with one item per argument. Without arguments, group1 defaults to zero (the whole match is returned).

.group()和.group(0)一样，返回的是全部的匹配内容

[wmttom]

>>> import re
>>> re.search(r"(?<=\()\S+?(?=\))", "aa(bbb)ccc").group()

[200cc]

var s = 'aa(bbb)ccc';
var r = /\((.*)\)/g;
var result = r.exec(s)[1]; // bbb

[RangerWolf]

@wmttom 赞！非常感谢！

[RangerWolf]

@zhyu 是的~ 只不过之前那位兄弟的正则 还是没把圆括号去掉