这道题算法题， python 怎么实现？

[webjin]

2 元钱一瓶啤酒， 4 个瓶子可以换 1 瓶啤酒， 2 个盖子可以换一瓶啤酒。问 10 元钱可以喝到多少批啤酒。这个用python怎么写出公式计算？

[aluo1]

def how_many_beer(money):
# The price of the beer
beer_price = 2

# The number of beer bought by the given money
beer_bought = money / beer_price
beer = beer_bought
# Bottle and lid number is the same as the beer bought initially
bottle = beer_bought
lid = beer_bought

# Check whether can trade in more beer
get_more_beer = tradable(bottle, lid)

while get_more_beer:
# Get the trade-in result
on_hand = trade_in(bottle, lid)

# Get the number of trade-in beer
more_beer = on_hand["beer"]
# Beer drunk so far
beer += more_beer
bottle = on_hand["bottle"] + more_beer
lid = on_hand["lid"] + more_beer

get_more_beer = tradable(bottle, lid)

return beer


def tradable(bottle,lid):
# How many bottle can trade in one beer
bottle_to_beer = 4
# How many lid can trade in one beer
lid_to_beer = 2

return (bottle / bottle_to_beer) | (lid/lid_to_beer)

def trade_in(bottle, lid):
# How many bottle can trade in one beer
bottle_to_beer = 4
# How many lid can trade in one beer
lid_to_beer = 2

beer_from_bottle = bottle / bottle_to_beer
beer_from_lid = lid / lid_to_beer
beer = beer_from_bottle + beer_from_lid

remained_bottle = bottle % bottle_to_beer
remained_lid = bottle % lid_to_beer

on_hand = {"beer": beer,
"bottle": remained_bottle,
"lid": remained_lid}

return on_hand

print how_many_beer(10)

应该没错吧。。。求大神指教

[aluo1]

def how_many_beer(money):
# The price of the beer
beer_price = 2

# The number of beer bought by the given money
beer_bought = money / beer_price
beer = beer_bought
# Bottle and lid number is the same as the beer bought initially
bottle = beer_bought
lid = beer_bought

# Check whether can trade in more beer
get_more_beer = tradable(bottle, lid)

while get_more_beer:
# Get the trade-in result
on_hand = trade_in(bottle, lid)

# Get the number of trade-in beer
more_beer = on_hand["beer"]
# Beer drunk so far
beer += more_beer
bottle = on_hand["bottle"] + more_beer
lid = on_hand["lid"] + more_beer

get_more_beer = tradable(bottle, lid)

return beer


def tradable(bottle,lid):
# How many bottle can trade in one beer
bottle_to_beer = 4
# How many lid can trade in one beer
lid_to_beer = 2

return (bottle / bottle_to_beer) | (lid/lid_to_beer)

def trade_in(bottle, lid):
# How many bottle can trade in one beer
bottle_to_beer = 4
# How many lid can trade in one beer
lid_to_beer = 2

beer_from_bottle = bottle / bottle_to_beer
beer_from_lid = lid / lid_to_beer
beer = beer_from_bottle + beer_from_lid

remained_bottle = bottle % bottle_to_beer
remained_lid = bottle % lid_to_beer

on_hand = {"beer": beer,
"bottle": remained_bottle,
"lid": remained_lid}

return on_hand

print how_many_beer(10)

[aluo1]

为什么空格不对。。。

[webjin]

@aluo1 a 好像都允许不起来

[aluo1]

@webjin 欸？运行不起来嘛？是不是空格打错了