捣鼓一下午到现在还没解决的一句简单 SQL 语句求赐教:两张表关联查询求总数降序排列

2015-12-08 21:25:25 +08:00
 jookr
表 member


表 city



查表 [ member as m ] 的数据总量 [ count(*) as total ]
顺带一起展示 city 表的 [ c.id,c.city_name,c.pinyin ]
关联另外一张表 [ left join city as c ]
关系是 member 的 m.from 关联 city 的 c.pinyin [ on m.from=c.pinyin ]
按照 c.pinyin 分组 [ group by c.pinyin ]
按照 total 降序排列 [ order by total desc ]


自己测试过以下语句
select c.id,c.city_name,c.pinyin,count(*) as total
from `city` as c
left join `member` as m on m.from = c.pinyin
group by c.pinyin
order by total desc
空记录的深圳本该是 0 ,但是查出来竟然是 1 。


select c.id,c.city_name,c.pinyin,count(*) as total
from `city` as c
left join `member` as m on m.from = c.pinyin
group by c.id
order by total desc
空记录的深圳本该是 0 ,但是查出来竟然是 1 。

select c.id,c.city_name,c.pinyin,count(*) as total
from `city` as c
left join `member` as m on m.from = c.pinyin
group by c.city_name
order by total desc
空记录的深圳本该是 0 ,但是查出来竟然是 1 。

以上三条 sql 结果一样,如下图

=================================


select c.id,c.city_name,c.pinyin,count(*) as total
from `member` as m
left join `city` as c on m.from = c.pinyin
group by m.from
order by total desc
少了 0 数据的深圳,数据不全。

select c.id,c.city_name,c.pinyin,count(*) as total
from `member` as m
left join `city` as c on m.from = c.pinyin
group by c.city_name
order by total desc
少了 0 数据的深圳,数据不全。

select c.id,c.city_name,c.pinyin,count(*) as total
from `member` as m
left join `city` as c on m.from = c.pinyin
group by c.pinyin
order by total desc
少了 0 数据的深圳,数据不全。

以上三条 sql 结果一样,如下图


=====================================
--
-- 表的结构 `city`
--

CREATE TABLE IF NOT EXISTS `city` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`city_name` varchar(30) NOT NULL,
`pinyin` varchar(30) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=MyISAM DEFAULT CHARSET=utf8 AUTO_INCREMENT=6 ;


INSERT INTO `city` (`id`, `city_name`, `pinyin`) VALUES
(1, '北京', 'beijing'),
(2, '上海', 'shanghai'),
(3, '广州', 'guangzhou'),
(4, '深圳', 'shenzhen'),
(5, '未知', '');
================================

--
-- 表的结构 `member`
--

CREATE TABLE IF NOT EXISTS `member` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`name` varchar(30) NOT NULL,
`from` varchar(30) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=MyISAM DEFAULT CHARSET=utf8 AUTO_INCREMENT=10 ;



INSERT INTO `member` (`id`, `name`, `from`) VALUES
(1, 'a1', 'beijing'),
(2, 'a2', 'beijing'),
(3, 'a3', 'beijing'),
(4, 'a4', 'shanghai'),
(5, 'a5', 'shanghai'),
(6, 'a6', 'guangzhou'),
(7, 'a7', ''),
(8, 'a8', ''),
(9, 'a9', '');
==================================
请问如何写这条 sql 语句才能正确的查询如第一段想要的结果呢?
2557 次点击
所在节点    MySQL
5 条回复
terence4444
2015-12-08 21:34:40 +08:00
粗看了一下,你把 city 表放左边似乎是不对的,应该挂右表。
cxbig
2015-12-08 21:38:37 +08:00
跟 city 相关的信息都放 city 表,和 member 的关联只给一个 city_id 。
统计的时候 city 做主表,连上 member , count 一下就好。
alex321
2015-12-08 21:41:19 +08:00
SELECT `member`.*,`city`.*,count(`member`.id) AS total
FROM member
RIGHT JOIN city ON `member`.`from`=`city`.`pinyin`
GROUP BY `city`.`id`
ORDER BY total DESC

你要统计的是按照城市来,请使用 right join 。。
jookr
2015-12-08 21:47:56 +08:00
原来如此 谢谢各位
看来得重温 mysql 基础知识了
soolby
2015-12-24 12:19:33 +08:00
过来问问楼主你还健身吗?

这是一个专为移动设备优化的页面(即为了让你能够在 Google 搜索结果里秒开这个页面),如果你希望参与 V2EX 社区的讨论,你可以继续到 V2EX 上打开本讨论主题的完整版本。

https://www.v2ex.com/t/242087

V2EX 是创意工作者们的社区,是一个分享自己正在做的有趣事物、交流想法,可以遇见新朋友甚至新机会的地方。

V2EX is a community of developers, designers and creative people.

© 2021 V2EX