请教一个字符串截取问题

[Curtain]

例如 url ：
xxx/xxx-102.html
xxx/xxx-43.html

想通过"-"以及"."去定位中字符串并存入列表.
请问如何实现?

[okletswin]

re.match(r'.*-([^\.]+)\.', 'xxx-102.html')

[fei051466]

>>> target = 'xxx/xxx-102.html'
>>> result = target[target.find('-') + 1: target.find('.')]
>>> result
'102'

[leavic]

不想用 re 就做两次 split

[zhicheng]

>>> 'xxx/xxx-102.html'.rpartition('-')[2].partition('.')[0]
'102'
>>> 'xxx/xxx-43.html'.rpartition('-')[2].partition('.')[0]
'43'
>>> ''.rpartition('-')[2].partition('.')[0]
''
>>> '-------------'.rpartition('-')[2].partition('.')[0]
''
>>> '.........'.rpartition('-')[2].partition('.')[0]
''
>>> '-.-.-.-.-.-.'.rpartition('-')[2].partition('.')[0]
''
>>> '-123.-456.-789.-123.-456.-789.'.rpartition('-')[2].partition('.')[0]
'789'
>>> 'laksdjflkajs8923u41--..asdf92u34100---12342.'.rpartition('-')[2].partition('.')[0]
'12342'

[imn1]

In [4]: import re

In [5]: re.split(r'[.\-]', 'xxx/xxx-102.html')
Out[5]: ['xxx/xxx', '102', 'html']

[mringg]

题主是老司机，鉴定完毕

[Antidictator]

@mringg 你也是老司机鉴定完毕

[Curtain]

@imn1 好用。谢谢

[ijustdo]

>>> a = 'xxx/xxx-102.html'
>>> a.rsplit('.', 1)[0].rsplit('-', 1)[-1]

[ijustdo]

大家要考虑 xxx/xxx 里面也可能包含 . 或者 - 的情况 呵呵 永远不要相信任何输入