求助各位大神, 如何将(a,(b,(c,(d,(e,(f))))))转换为(f,(e,(d,(c,(b,(a))))))

[koplyp]

[fortunezhang]

str1 = '(a,(b,(c,(d,(e,(f,g)))))))'
str1 = str1.replace(')', ' ').replace('(', ' ').replace(',', ' ')
str1 = str1[::-1].split()
str1 = '(' + ',('.join(str1) + ')' * len(str1)
print(str1)

[gowl]

@Antidictator 多谢～

[gowl]

https://i.loli.net/2018/03/19/5aaf74dfa9db4.jpg

[gowl]

[dizzy]

@param 请问手机上使用 ipython 是什么软件？

[param]

@dizzy termux

[tihiro]

def get_elements(s):
q = []
while len(s) != 1:
q.append(s[0])
s = s[1]
q.append(s)

return q


def nested_list(l):
res = ()
ele0 = l[0]
res += (ele0, )
l.remove(ele0)
if len(l) > 0:
res += ((nested_list(l), ))

return res


def main():
s = ('a', ('b', ('c', ('d', ('e', ('f'))))))
l = get_elements(s)
l = l[::-1]
ll = nested_list(l)
print(ll)


if __name__ == '__main__':
main()

[xiongshengyao]

最简单的思路…一个队列一个栈
```
def main(source_str):
el = []
ret = []
for i in source_str:
if i not in ('(', ',', ')'):
el.append(i)
ret.append("#")
else:
ret.append(i)

for index, value in enumerate(ret):
if value == "#":
ret[index] = el.pop()

return "".join(ret)


if __name__ == "__main__":
result = main("(a,(b,(c,(d,(e,(f))))))")
print(result)
```