点击“link my twitter account”,返回以下错误,请问是什么原因?谢谢!
Traceback (most recent call last):
File "/base/python_runtime/python_lib/versions/1/google/appengine/ext/webapp/
__init__.py", line 511, in __call__
handler.get(*groups)
File "/base/data/home/apps/*****/1.346122954668006233/
t.py", line 50, in get
request_token = twitter.getRequestToken()
File "/base/data/home/apps/*****/1.346122954668006233/twitter/
oauthtwitter.py", line 189, in getRequestToken
resp = self._FetchUrl(url, no_cache=True)
File "/base/data/home/apps/*****/1.346122954668006233/twitter/
oauthtwitter.py", line 101, in _FetchUrl
url_data = opener.open(url).read()
File "/base/python_runtime/python_dist/lib/python2.5/
urllib2.py", line 387, in open
response = meth(req, response)
File "/base/python_runtime/python_dist/lib/python2.5/
urllib2.py", line 498, in http_response
'http', request, response, code, msg, hdrs)
File "/base/python_runtime/python_dist/lib/python2.5/
urllib2.py", line 425, in error
return self._call_chain(*args)
File "/base/python_runtime/python_dist/lib/python2.5/
urllib2.py", line 360, in _call_chain
result = func(*args)
File "/base/python_runtime/python_dist/lib/python2.5/
urllib2.py", line 506, in http_error_default
raise HTTPError(req.get_full_url(), code, msg, hdrs, fp)
HTTPError: HTTP Error 401: Unauthorized
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