如何将 1 个数组分割成相隔 1 的多个数组

[songdg]

array([ 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12,
13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25,
26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38,
39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51,
52, 69, 72, 73, 74, 75, 76, 77, 86, 97, 98, 100, 101,
102, 103, 104, 105, 106, 107, 108, 109, 110, 111, 112, 113, 114,
115, 116, 117, 118, 119, 120, 121, 122, 123, 124, 125, 126, 129,
130, 131, 142, 143, 144, 145, 146, 147, 148, 149, 150, 151, 152,
153, 154, 155, 156, 157, 158, 159, 160, 197, 198, 199, 200, 201,
202, 203, 204, 206, 207, 208, 209, 210, 216, 217, 218, 219, 220,
221, 222, 223, 224, 225, 226, 227, 228, 229, 230, 231, 232, 233,
234, 235, 236, 237, 239, 240, 241, 242, 243, 244, 259, 271, 272,
273, 274, 275, 276, 277, 278, 279, 280, 281, 282, 283, 284, 285,
286, 287, 288, 289, 290, 291, 292, 293, 294])

[songdg]

我的笨拙方法：
arr = array([ 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12,
13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25,
26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38,
39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51,
52, 69, 72, 73, 74, 75, 76, 77, 86, 97, 98, 100, 101,
102, 103, 104, 105, 106, 107, 108, 109, 110, 111, 112, 113, 114,
115, 116, 117, 118, 119, 120, 121, 122, 123, 124, 125, 126, 129,
130, 131, 142, 143, 144, 145, 146, 147, 148, 149, 150, 151, 152,
153, 154, 155, 156, 157, 158, 159, 160, 197, 198, 199, 200, 201,
202, 203, 204, 206, 207, 208, 209, 210, 216, 217, 218, 219, 220,
221, 222, 223, 224, 225, 226, 227, 228, 229, 230, 231, 232, 233,
234, 235, 236, 237, 239, 240, 241, 242, 243, 244, 259, 271, 272,
273, 274, 275, 276, 277, 278, 279, 280, 281, 282, 283, 284, 285,
286, 287, 288, 289, 290, 291, 292, 293, 294])
brr = np.append(arr,arr[-1] + 1)
crr = np.where(brr[1:] - arr != 1)
drr = []
k = 0
for i in crr:
devi.append(arr[k:i])
k = i
devi.append(arr[i:])

[epicnoob]

看不懂你的要求，代码也执行不了。

[zzj0311]

［::2 ］？看不懂代码+1

[songdg]

不能修改帖子，只能在这里修改有错的代码：
arr = array([ 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12,
13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25,
26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38,
39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51,
52, 69, 72, 73, 74, 75, 76, 77, 86, 97, 98, 100, 101,
102, 103, 104, 105, 106, 107, 108, 109, 110, 111, 112, 113, 114,
115, 116, 117, 118, 119, 120, 121, 122, 123, 124, 125, 126, 129,
130, 131, 142, 143, 144, 145, 146, 147, 148, 149, 150, 151, 152,
153, 154, 155, 156, 157, 158, 159, 160, 197, 198, 199, 200, 201,
202, 203, 204, 206, 207, 208, 209, 210, 216, 217, 218, 219, 220,
221, 222, 223, 224, 225, 226, 227, 228, 229, 230, 231, 232, 233,
234, 235, 236, 237, 239, 240, 241, 242, 243, 244, 259, 271, 272,
273, 274, 275, 276, 277, 278, 279, 280, 281, 282, 283, 284, 285,
286, 287, 288, 289, 290, 291, 292, 293, 294])
brr = np.append(arr,arr[-1] + 1) #使 brr 为 array([ 0, 1, 2, ......, 293, 294, 295])
crr = np.where(brr[1:] - arr != 1)
drr = []
k = 0
for i in crr:
drr.append(arr[k:i])
k = i
drr.append(arr[i:])

[swulling]

你贴示例数组，是不是贴十来个元素就可以了，至于贴这么长的么

[GeruzoniAnsasu]

随意到底是想干嘛都没说清楚？

[songdg]

就是数组[ 0, 1, 2, 3, 6, 7, 8, 9, 10, 12, 14, 15, 16, 17, 18, 19, 23, 24, 27, 28, 29, 30]分割成[ 0, 1, 2, 3][6, 7, 8, 9, 10][12][14, 15, 16, 17, 18, 19][23, 24][27, 28, 29, 30]

[whoami9894]

@songdg 你这分割的长度是依照什么

[wingkou]

@songdg 早说这个不就行了吗，是把大数组分割成元素连续的一个个数组吧？你大数组一定是升序的吗？

[menc]

最简解法只需要一行

[menc]

[songdg]

@menc 非常感谢帮助。

[msg7086]

无序的话可以用双向头尾哈希表，有序的话直接遍历搜索 arr[i] - arr[i-1] != 1 就行了。

[necomancer]

In [1]: a = np.array([ 0, 1, 2, 3, 6, 7, 8, 9, 10, 12, 14, 15, 16, 17, 18, 19, 23, 24, 27, 28, 29, 30])

In [2]: np.split(a,np.argwhere(np.diff(a-np.arange(a.shape[0]))!=0).flatten()+1)
Out[2]:
[array([0, 1, 2, 3]),
array([ 6, 7, 8, 9, 10]),
array([12]),
array([14, 15, 16, 17, 18, 19]),
array([23, 24]),
array([27, 28, 29, 30])]

[songdg]

@msg7086 谢谢帮助。

[songdg]

@necomancer @msg7086 谢谢帮助。