Python 作业求教，矩阵转置

[HHH01]

又有一题不是特别会做，求教大家， 需要用 python 写一个 function 去得出某个二维矩阵的转置矩阵。 好像看起来挺简单，转置矩阵就是 Nij=Nji，但是还没想到思路。因此求教大神。

如题，

Exercise 4. Within the module matrix_utils.py write a function transpose() . The function should accept one parameter matrix which is a two-dimensional matrix (in Python it is a list of lists of the same size). The function should return a transposed matrix. Example usages of this functions: matrix1 = [[0, 1, 2, 3, 4], [0, 1, 2, 3, 4] ] print("Transposed:", transpose(matrix1)) Transposed: [[0, 0], [1, 1], [2, 2], [3, 3], [4, 4]] matrix2 = [[ ' a ' , ' b ' ], [ ' c ' , ' d ' ] ] print("Transposed:", transpose(matrix2)) Transposed: [[ 'a ' , ' c '] , [ 'b ' , ' d ']]

[KylinJiang]

emmm 不太在意性能的话：

[KylinJiang]

map(list,zip(*N))
N 为你的多维数组

[HHH01]

@KylinJiang 不能用 zip，还没学到，用 lists 的 loop。。。

[HHH01]

我想到的思路，但是有问题
def transpose(matrix):
matrix == list
n = len(matrix)
tran_m = []
m=0
for m in range(0,n):
m += len(matrix[m])

temp=[]
for i in range(n):
tran_m=tran_m+[temp]

for j in range(m):
temp=temp+[matrix[j][i]]

return tran_m

[HHH01]

想到了！
def transpose(matrix):
matrix == list

tran_m = []

for i in range(len(matrix[0])):
temp=[]

for j in range(len(matrix)):
temp=temp+[matrix[j][i]]
tran_m=tran_m+[temp]

return tran_m

[cherbim]

```
def transpose(m):
result = []
row = len(m)
col = len(m[0])
for i in range(col):
item = []
for index in range(row):
item.append(m[index][i])
result.append(item)
return result


matrix1 = [[0, 1, 2, 3, 4], [0, 1, 2, 3, 4]]
print("Transposed:", transpose(matrix1))
```

[cherbim]

获得行数和列数，然后调一下行和列存入另一个矩阵

[TimePPT]

进来学习。

以及，每次看到这种题就感慨 numpy 真香 😂

[Trim21]

@TimePPT import numpy 交作业可还行 233

[009694]

t = [[1,2,3],[4,5,6]]
t_t = [[row[i] for row in t] for i in range(max(len(t) for t in t))]

[009694]

transpose = lambda t:[[row[i] for row in t] for i in range(max(len(t) for t in t))]

[TimePPT]

@Trim21 老师让你用锤子锯子钳子做把椅子，你转身去库房拉了个数控机床😂

[ddzzhen]

pandas 直接 T 就行了

[xiri]

emmmm，如果不是作业的话 numpy 分分钟就 over 了

[coordinate]

for i in range(len(mat)):
for j in range(i+1, len(mat[0])):
mat[i][j], mat[j][i] = mat[j][i], mat[i][j]

[necomancer]

traspose = lambda x : [ [x[i][j] for i in range(len(x))] for j in range(len(x[0]))]

转置只能对 (mxn) 形状的列表有效。

[HHH01]

@TimePPT 还没学到，不能用啊

[HHH01]

还是众人拾柴火焰高

[cshlxm]

import numpy 哈哈哈
list 的话，只能读一行，再循环每一行 append 一个对应数

[yuuiasuka]

可以参考下 numpy 里面的 transpose 方法是怎么实现的。