菜鸟请教一个Python正则问题

[kenneth]

https://gist.github.com/kenneth/5633351

想去掉content中的ubb，只要链接，应该如何写？

请高手赐教。

[jason52]

您是想抓图？哪里有ubb呢？

[jason52]

you mean URL?

[KotiyaSanae]

```python
import re
content="""
[URL="http://www.boston.com/bigpicture/2008/10/the_sun.html"]http://www.boston.com/bigpictu....html[/URL]
[url="http://www.boston.com/bigpicture/2008/10/the_sun.html"]http://www.boston.com/bigpictu....html[/url]
[URL=http://www.boston.com/bigpicture/2008/10/the_sun.html]http://www.boston.com/bigpictu....html[/URL]
[url=http://www.boston.com/bigpicture/2008/10/the_sun.html]http://www.boston.com/bigpictu....html[/url]
[url]http://www.boston.com/bigpictu....html[/url]
[URL]http://www.boston.com/bigpictu....html[/URL]
"""
pattern = r'.*(http://.*html?).*'
pat = re.compile(pattern)
pat.findall(content)
```

[dreampuf]

http://www.debuggex.com/r/ttJaqDfUeY7iqDYO/0
有2 取2 ，没2 取4

[dreampuf]

import re
re.search("\\[(?:([^=]+)=([^\\]]+)|([^\\]]+))\\]([^\\[]+)\\[/(?:\\1|\\3)\\]", searchText)

[kenneth]

@dreampuf
@jason52
@KotiyaSanae

http://www.debuggex.com/r/rCd3ctt_HxUG5roq/0

[KotiyaSanae]

@kenneth 没太看懂你要匹配什么，是所有的boston么？那个网站不太会用……
pattern = r'.*](http://.*html?).*' ？ python环境下通过……

[jason52]

这种事强烈推荐用pyquery做 代码可以很简单 抓图代码就这么一点
http://dpaste.com/1196576/

[jason52]

@KotiyaSanae 如果用re的话这种可以