一段 html 格式数据流，怎么截取某个字段最简单粗暴？

[tyit]

文本太长省略.................

to the xxxx:

• href="xxxxxxxx222xx/ipv4/192.168.108.153">192.168.108.153
• href="xxxxxxxx11xxx/ipv4/192.168.109.153">192.168.109.153
• href="x/xxx3x33xxxx/ipv4/192.168.110.153">192.168.110.153
• href="xx55xxxxx5xx/ipv4/192.168.111.153">192.168.111.153
• href="xxxxxxx222xx/ipv4/192.168.108.153">192.168.108.153
• href="xxxxxxx11xxx/ipv4/192.168.109.153">192.168.109.153
• href="x/3xxx33xxxx/ipv4/192.168.110.153">192.168.110.153
• href="xx55xxxx5xx/ipv4/192.168.111.153">192.168.111.153
• href="xxxxxx222xx/ipv4/192.168.108.153">192.168.108.153
• href="xxxxxxxx11xxx/ipv4/192.168.109.153">192.168.109.153
• href="x/xxx3x33xxxx/ipv4/192.168.110.153">192.168.110.153
• href="xx55xxxxx5xx/ipv4/192.168.111.153">192.168.111.153

• "@type":"Qxxxxxn","name":"xxxxx

  文本太长省略.................

  目的截取这四个 IP，其中这四个 IP 会不定期的无规律随机变动

  192.168.108.153

  192.168.109.153

  192.168.110.153

  192.168.111.153

[OhYee]

最简单肯定是正则表达式吧

[jifengg]

这么有规则，当然是用正则表达式了。