请教各位，如何解决 warning: stack protector not protecting local variables: variable length buffer

[fenglala]

编译器: https://releases.linaro.org/components/toolchain/binaries/7.5-2019.12/arm-eabi/gcc-linaro-7.5.0-2019.12-x86_64_arm-eabi.tar.xz

test.c:

struct Foo{
    char a[32]; // 32 and above will produce warning, but 31 and below will not
    char d[9]; // 9 and above will produce warning, but 8 and below will not
};

int main()
{
    struct Foo foo = {0};
    (void)(foo);
    return 0;
}

编译命令及输出：

$ arm-eabi-gcc -Wstack-protector -fstack-protector-all -fstack-check -o test test.c
test.c: In function ‘main’:
test.c:6:5: warning: stack protector not protecting local variables: variable length buffer [-Wstack-protector]
 int main()
     ^~~~

实际代码中的结构体类似上文的 Foo ，我不能改，但是 main 我可以改，请问怎么改 main 能解决这个 warning ？

感谢各位！

各位也可以去 https://stackoverflow.com/questions/70133887/how-can-i-fix-warning-stack-protector-not-protecting-local-variables-variable 上回答，我 Google 了一圈都没找到怎么解。

[wudicgi]

#pragma 直接屏蔽掉这个 warning [狗头]

https://github.com/search?l=C&p=2&q=stack+protector+not+protecting+local+variables&type=Code

https://github.com/solomonndungu/kubernetes/blob/ad220b896530cfce895a47188e66235686e79e6c/kubernetes_test/keepalived-2.0.15/lib/warnings.h#L45

[fenglala]

@wudicgi 是个办法，直接去掉-Wstack-protector 或许更直接🐶

[ExplorerLog]

static ?