我倒是觉得程序员分这样2类

[kurtis]

Type I.
proc1();
proc2();

Type II.
proc1(proc2);

[mikawudi]

Func<Func<int, int>, int, Func<int, int>, int, int> sum = (term, a, next, b) =>
{
Func<int, int, int> iter = null;
iter = (a1, result) =>
{
if (a1 > b)
return result;
else
return iter(next(a1), term(a1) + result);
};
return iter(a, 0);
};
int ss = sum((x) => { return x; }, 1, (i) => { return i + 1; }, 10);
C#版本.....简单来说是做累加,不过写的更泛用了....步长和每一次对累加值可以进行自定义....差不多这个意思?....写完才发现lambda表达式貌似不能递归自己....还要显示声明下再用引用来递归...好难受

[mikawudi]

@dorentus CPS变换了...其实做的是一回事

[wity_lv]

@loading
@housne
@yuankui
@mikawudi
给一个javascript版本, 用高阶函数做抽象.
function sum (term, a, next, b) {
function iter (a, result) {
if (a > b) {
return result;
}

var ret = term(a) + result;
return iter(next(a), ret);
}

return iter(a, 0);
}

var all = sum(function(x) {
return x;
}, 1,
function(x) {
return x + 1;
}, 100);

console.log(all);

[wity_lv]

@loading
@housne
@yuankui
@mikawudi
贴代码太蛋疼了，传送门:
https://github.com/lvjian700/fp-workshop/blob/master/sum.js

[mikawudi]

@wity_lv 看了下哥们的帖子。。。。果然看到了sicp

[nybux]

#include <iostream>
#include <functional>
template<typename F1, typename F2, typename T>
int sum(F1 term, T a, F2 next, T b) {
std::function<int(T,T)> iter = [&](T a, T result){
return (a > b) ? result : iter(next(a), term(a) + result);
};
return iter(a, 0);
}
int main() {
int all = sum([](int x) { return x; }, 1, [](int x) { return x + 1;}, 100);
std::cout << all << std::endl;
}

[halfblood]

过程式和函数式而已！
整天讨论这些有毛用啊……