Python “Reverse Integer”问题求解答

[imkh]

在LeetCode上有一道“Reverse Integer”的题 ，https://oj.leetcode.com/problems/reverse-integer/
但用Python解决时会出现下面的问题，该怎么解答呢？
```python
class Solution:
# @return an integer
def reverse(self, x):
if x >= 0 :
return int(str(x)[::-1])
else:
return -1*int(str(-1*x)[::-1])
Submission Result: Wrong Answer
```
Input: 1534236469
Output: 9646324351
Expected: 0

Python里，当int溢出时，不是会自动类型转换为long吗？
那这道题该怎么做才能提交？

For the purpose of this problem, assume that your function returns 0 when the reversed integer overflows.

[virusdefender]

Did you notice that the reversed integer might overflow? Assume the input is a 32-bit integer, then the reverse of 1000000003 overflows. How should you handle such cases?

For the purpose of this problem, assume that your function returns 0 when the reversed integer overflows.

你没看提示啊

[virusdefender]

python 的话也要按照32位数来算

[imkh]

@virusdefender 那怎样按照32位数来算？

[virusdefender]

@imkh 判断一下是不是超过32位数的范围啊

[imkh]

@virusdefender 感谢。