date rtn 0 2016-01-01 0.101536 1 2016-01-02 0.055109 2 2016-01-03 -0.163625 3 2016-01-04 0.086756 4 2016-01-05 0.035907 5 2016-01-06 0.047619 6 2016-01-07 0.018717 7 2016-01-08 -0.036290
这样子的 df
大佬帮帮忙，实在搞不出来了
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This topic created in 2919 days ago, the information mentioned may be changed or developed.
6 replies • 2018-09-29 15:32:59 +08:00
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1
neosfung Sep 28, 2018
df['rtn'] = df['rtn'].apply(lambda x: 1 if x>0 else x)
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2
jswangjieda Sep 28, 2018
df.loc[df['rtn']>0,'rtn']=1
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3
ddzzhen Sep 28, 2018 via Android
直接改为 true，false 矩阵
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4
lieh222 Sep 29, 2018
x = x**0
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6
LaFayette Sep 29, 2018
df['rtn'] = np.where(df['rtn']>0, 1, df['rtn'])
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