新算法:
for i = 1 to n do
for j = 1 to n do
if A[i] < A[j] then
swap A[i] and A[j]
等价的冒泡排序算法:
for i = 1 to n do
for j = i + 1 to n do
if A[i] > A[j] then
swap A[i] and A[j]
算法来源: https://arxiv.org/pdf/2110.01111.pdf
for i = 1 to n do
for j = 1 to n do
if A[i] < A[j] then
swap A[i] and A[j]
等价的冒泡排序算法:
for i = 1 to n do
for j = i + 1 to n do
if A[i] > A[j] then
swap A[i] and A[j]
算法来源: https://arxiv.org/pdf/2110.01111.pdf