推荐学习书目
› Learn Python the Hard Way
Python Sites
› PyPI - Python Package Index
› http://diveintopython.org/toc/index.html
› Pocoo
值得关注的项目
› PyPy
› Celery
› Jinja2
› Read the Docs
› gevent
› pyenv
› virtualenv
› Stackless Python
› Beautiful Soup
› 结巴中文分词
› Green Unicorn
› Sentry
› Shovel
› Pyflakes
› pytest
Python 编程
› pep8 Checker
Styles
› PEP 8
› Google Python Style Guide
› Code Style from The Hitchhiker's Guide
SystemLight
V2EX  ›  Python

fastapi+pydantic+sqlalchemy 如何返回列表数据?

  •  
  •   SystemLight ·
    SystemLight · Dec 16, 2021 · 3458 views
    This topic created in 1743 days ago, the information mentioned may be changed or developed.
    • pydantic 可以格式化 ORM 模型,但是如何能返回列表类型
    • [Model,Model,Model] 这种格式如何通过 pydantic 验证
    3 replies  •  2021-12-18 15:47:14 +08:00
    NCZkevin
        1
    NCZkevin  
       Dec 16, 2021
    from typing import List
    List[Model]
    4BVL25L90W260T9U
        2
    4BVL25L90W260T9U  
       Dec 17, 2021   ❤️ 1
    首先,restful 接口返回 list 不是一个最佳实践。如果你直接返回了一个 list ,翻页信息放到哪儿呢?所以最好还是返回一个特定的对象,而不是“裸” list 。比如:

    ```py
    class Item(BaseModel):
    pass

    class Res(BaseModel):
    page: int
    page_size: int
    items: list[Item]
    ```
    luckyc
        3
    luckyc  
       Dec 18, 2021
    @ospider 我更倾向于
    {
    "code": 0,
    "msg":"ok",
    "data":{
    "page":1,
    "page_size":100,
    "items":[...]
    }
    }
    About   ·   Help   ·   Advertise   ·   Blog   ·   API   ·   FAQ   ·   Privacy   ·   Solana   ·   873 Online   Highest 6679   ·     Select Language
    创意工作者们的社区
    World is powered by solitude
    VERSION: 3.9.8.5 · 35ms · UTC 22:02 · PVG 06:02 · LAX 15:02 · JFK 18:02
    ♥ Do have faith in what you're doing.