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nowcoder
V2EX  ›  程序员

牛客网在线编程比赛题目代码公布,欢迎收藏, V 友你们可以做出几个?

  •  
  •   nowcoder · 2015-03-13 10:09:41 +08:00 · 4734 次点击
    这是一个创建于 3568 天前的主题,其中的信息可能已经有所发展或是发生改变。

    感谢小伙伴的热情参与,比赛的编程题目现在已经开放,大家可以随时自我挑战。
    第一场 http://www.nowcoder.com/test/5409/summary?from=v2ex
    第二场 http://www.nowcoder.com/test/6091/summary?from=v2ex

    稍后放出比赛排行版,以下是用户提交的最优解
    第一场
    第一题 http://www.nowcoder.com/questionTerminal/b89b14a3b5a94e438b518311c5156366

    public class Solution {
        /**
         *  奇数位上都是奇数或者偶数位上都是偶数
         *  输入:数组arr,长度大于2
         *  将arr调整成奇数位上都是奇数或者偶数位上都是偶数
         */
        public void oddInOddEvenInEven(int[] arr) {
            if (arr == null || arr.length < 2) {
                return;
            }
            int evenIndex = 0;
            int oddIndex = 1;
            int endIndex = arr.length - 1;
            while (evenIndex < arr.length && oddIndex < arr.length) {
                if ((arr[endIndex] & 1) == 0) {
                    swap(arr, endIndex, evenIndex);
                    evenIndex += 2;
                } else {
                    swap(arr, endIndex, oddIndex);
                    oddIndex += 2;
                }
            }
        }
    
        public void swap(int[] arr, int a, int b) {
            int tmp = arr[a];
            arr[a] = arr[b];
            arr[b] = tmp;
        }
    }
    

    第二题 http://www.nowcoder.com/questionTerminal/296c2c18037843a7b719cf4c9c0144e4

    import java.util.HashSet;
    
    public class Solution {
        /**
         *  正数数组中的最小不可组成和
         *  输入:正数数组arr
         *  返回:正数数组中的最小不可组成和
         */
        public int getFirstUnFormedNum(int[] arr) {
            if (arr == null || arr.length == 0) {
                return 1;
            }
            HashSet<Integer> sumSet = new HashSet<Integer>();
            HashSet<String> isCompute = new HashSet<String>();
            setSumSetProcessDP(arr, 0, 0, isCompute, sumSet);
            int min = Integer.MAX_VALUE;
            for (int i = 0; i != arr.length; i++) {
                min = Math.min(min, arr[i]);
            }
            for (int i = min; i != Integer.MIN_VALUE; i++) {
                if (!sumSet.contains(i)) {
                    return i;
                }
            }
            return 0;
        }
    
        public void setSumSetProcessDP(int[] arr, int index, int preSum,
                HashSet<String> isCompute, HashSet<Integer> sumSet) {
            String curKey = String.valueOf(index + "+" + preSum);
            if (isCompute.contains(curKey)) {
                return;
            }
            if (index == arr.length) {
                sumSet.add(preSum);
                isCompute.add(curKey);
                return;
            }
            setSumSetProcessDP(arr, index + 1, preSum, isCompute, sumSet);
            setSumSetProcessDP(arr, index + 1, preSum + arr[index], isCompute, sumSet);
            isCompute.add(curKey);
        }
    
    }
    

    第三题 http://www.nowcoder.com/questionTerminal/3e6310ec9fb6445c814d4e0e21692f04

    public class Solution {
        /**
         *  得到硬币博弈问题的获胜分值
         *  输入:代表硬币排列情况的数组arr
         *  返回:硬币博弈问题的获胜分值
         */
        public int getWinValue(int[] arr) {
            int[][] map = new int[arr.length][arr.length];
            int player1Value = getOptimale(arr, 0, arr.length - 1, map);
            int player2Value = getArraySum(arr) - player1Value;
            return Math.max(player1Value, player2Value);
        }
    
        public int getOptimale(int[] arr, int start, int end, int[][] map) {
            if (start == end) {
                return arr[start];
            }
            if (map[start][end] != 0) {
                return map[start][end];
            }
            int result = Math.max(
                    arr[start] + getMinRest(arr, start + 1, end, map), arr[end]
                            + getMinRest(arr, start, end - 1, map));
            map[start][end] = result;
            return result;
        }
    
        public int getMinRest(int[] arr, int start, int end, int[][] map) {
            if (start == end) {
                return 0;
            }
            return Math.min(getOptimale(arr, start + 1, end, map),
                    getOptimale(arr, start, end - 1, map));
        }
    
        public int getArraySum(int[] arr) {
            int result = 0;
            for (int i = 0; i != arr.length; i++) {
                result += arr[i];
            }
            return result;
        }
    
    }
    

    第二场
    第一题 http://www.nowcoder.com/questionTerminal/498a758089e4472f8698092295e45ce4

    public class Solution {
        /**
         *  求左部分中的最大值减去右部分最大值的绝对值
         *  arr:输入数组
         *  返回:左部分中的最大值减去右部分最大值的绝对值
         */
        public int getMaxABSLeftAndRight(int[] arr) {
            int max = Integer.MIN_VALUE;
            for (int i = 0; i != arr.length; i++) {
                max = Math.max(arr[i], max);
            }
            return max - Math.min(arr[0], arr[arr.length - 1]);
        }
    }
    

    第二题 http://www.nowcoder.com/questionTerminal/56f059fc033f46b98c73e2caea760a8d

    public class Solution {
        /**
         *  按照左右半区的方式重新组合单链表
         *  输入:一个单链表的头节点head
         *  将链表调整成题目要求的样子
         *
         *  后台的单链表节点类如下:
         *
         public class ListNode {
            int val;
            ListNode next = null;
    
            ListNode(int val) {
                this.val = val;
            }
        }
         */
    
        public void relocateList(ListNode head) {
            if (head == null || head.next == null) {
                return;
            }
            ListNode head2 = null;
            if (head.next.next == null || head.next.next.next == null) {
                head2 = head.next;
                head.next = null;
                mergeLinkedList(head, head2);
                return;
            }
            boolean midMove = true;
            ListNode midNode = head;
            ListNode cur = head.next.next.next;
            while (cur != null) {
                if (midMove) {
                    midNode = midNode.next;
                }
                midMove = !midMove;
                cur = cur.next;
            }
            head2 = midNode.next;
            midNode.next = null;
            mergeLinkedList(head, head2);
        }
    
        public void mergeLinkedList(ListNode head1, ListNode head2) {
            ListNode cur1 = head1;
            ListNode cur2 = head2;
            while (cur1.next != null) {
                ListNode nextCur1 = cur1.next;
                ListNode nextCur2 = cur2.next;
                cur1.next = cur2;
                cur2.next = nextCur1;
                cur1 = nextCur1;
                cur2 = nextCur2;
            }
            cur1.next = cur2;
        }
    
    }
    

    第三题 http://www.nowcoder.com/questionTerminal/f2981aa0dc4a4b2190a0f26b7003a688

    public class Solution {
        /**
         *  将路径数组变为统计数组
         *  输入:代表一张图的数组paths
         *  将paths数组变为距离数组numArr
         */
        public void pathArrToNumArr(int[] paths) {
            if (paths == null || paths.length == 0) {
                return;
            }
            // citiesPath -> distancesArray
            pathArrToDistanceArr(paths);
    
            // distancesArray -> numArray
            distanceArrToNumArr(paths);
        }
    
        public void pathArrToDistanceArr(int[] paths) {
            int cap = 0;
            for (int i = 0; i != paths.length; i++) {
                if (paths[i] == i) {
                    cap = i;
                } else if (paths[i] > -1) {
                    int curI = paths[i];
                    paths[i] = -1;
                    int preI = i;
                    while (paths[curI] != curI) {
                        if (paths[curI] > -1) {
                            int nextI = paths[curI];
                            paths[curI] = preI;
                            preI = curI;
                            curI = nextI;
                        } else {
                            break;
                        }
                    }
                    int value = paths[curI] == curI ? 0 : paths[curI];
                    while (paths[preI] != -1) {
                        int lastPreI = paths[preI];
                        paths[preI] = --value;
                        curI = preI;
                        preI = lastPreI;
                    }
                    paths[preI] = --value;
                }
            }
            paths[cap] = 0;
        }
    
        public void distanceArrToNumArr(int[] disArr) {
            for (int i = 0; i != disArr.length; i++) {
                int index = disArr[i];
                if (index < 0) {
                    disArr[i] = 0; // important
                    while (true) {
                        index = -index;
                        if (disArr[index] > -1) {
                            disArr[index]++;
                            break;
                        } else {
                            int nextIndex = disArr[index];
                            disArr[index] = 1;
                            index = nextIndex;
                        }
                    }
                }
            }
            disArr[0] = 1;
        }
    
    }
    
    2 条回复    2015-03-13 11:04:07 +08:00
    mailworks
        1
    mailworks  
       2015-03-13 10:57:53 +08:00
    这是Java语言写的吗?
    nowcoder
        2
    nowcoder  
    OP
       2015-03-13 11:04:07 +08:00
    @mailworks 是的。
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