super(type, obj) 和 super(type, type)的区别在哪？

[coordinate]

class Person:
    def __init__(self, name):
        self.name = name
    # Getter function
    @property
    def name(self):
        return self._name
    # Setter function
    @name.setter
    def name(self, value):       
        if not isinstance(value, str):
            raise TypeError('Expected a string')
        self._name = value
    # Deleter function
    @name.deleter
    def name(self):
        raise AttributeError("Can't delete attribute")

class SubPerson(Person):
    @property
    def name(self):
        print('Getting name')
        return super().name
    @name.setter
    def name(self, value):
        print('Setting name to', value)
        super(SubPerson, SubPerson).name.__set__(self, value)
    @name.deleter
    def name(self):
        print('Deleting name')
        super(SubPerson, SubPerson).name.__delete__(self)

s = SubPerson('Guido')
print(s.name)

当我将 super(SubPerson, SubPerson).name.__set__(self, value) 变成 super(SubPerson, self).name.__set__(self, value), 报了这样的错误

AttributeError: 'SubPerson' object has no attribute '_name'

为什么?

`super([type[, object-or-type]])` 显然是可以`super(SubPerson, SubPerson)`

If the second argument is omitted, the super object returned is unbound. If the second argument is an object, isinstance(obj, type) must be true. If the second argument is a type, issubclass(type2, type) must be true (this is useful for classmethods).

https://docs.python.org/2/library/functions.html#super

[ipwx]

标准里面没有 super(SubPerson, SubPerson) 这种写法吧……即使你手头的 CPython 能工作，也不代表未来的 CPython，或者别的 Python 比如 IronPython 和 PyPy 能工作。建议规避掉这种写法。

[coordinate]

我已经知道问题所在，结贴了：）